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better than most lectures!!!

You are single handedly getting me through physics 2 and I am so grateful!

That's a complicated way to calculate that value. It's much easier to do it using the ratio of the molar masses. That is why I do not understand the point of the whole exercise. Not your fault.

Hey, Glaser Tutoring!!! My additional physical properties that are shared by both solutions would include the fact that BOTH will be transparent and will not scatter light! Thanks, guys! Love your content!

Isn't the formula H2SO4 + 2NaOH -> Na2SO4 + 2H2O, so two times H+ and two times OH-? And the answer, therefore, 0.0068 M?

Hi, I am taking a second semester of General Chemistry after a year+ and you guys helped me so much through that first semester and I am so happy to be back on this channel with you helping me again. Thank you all so much for everything.

To get the atoms you have to multiply with 6,022 * 10^23. That's missing.

me.. thinking every time she asks at the end of these videos... What do you think?.... me saying: I think you are AMAZING!!!! Thanks for the explanations :)

"That's cooking with Christina" cracked me up.

ممكن صوتك يكون اللغه العربيه

Thank you for helping me get through physics!

I would expect both viscosity and surface tension to increase with increasing molecular forces. This seems to be true for viscosity, but the surface tension doesn't seem to follow the same trend and that puzzles me. Why does ethanol have a lower surface tension than acetone even though ethanol has hydrogen bonds and acetone does not? Acetone has a higher polarity (2.88 D) than diethyl ether (1.15 D), presumably because acetone is less symmetrical -- the oxygen sticks out more, but neither of these has hydrogen bonds. Ethanol has one hydrogen bonding site, while ethylene glycol has two. So I would expect that for both surface tension and viscosity we should get diethyl ether < acetone < ethanol < ethylene glycol. But this is not what I see.

I can’t believe I was literally just not thinking😭

This is the best tutorial I've ever watched on youtube. No joke. The calculator display on the left so my dumb*** doesn't get confused AND the thorough explanation. You the goat.

Great job and if you got this far congrats!! Great practice to clear some of the cobwebs away

You gotta STOP rounding in the middle of your problems because it is throwing your final answers off.

again you cant round in the mist of calculations. The answer should be .46m and 1.51ft/cubit.

it should be 93.5 in so the answer should be 603.22cm2 with becomes 6.0x10^2 cm2...you're answers tend to be off by a little bit here and there. I hope this adds context for anyone watching. Anyways, I like your videos great help in checking answers for correctness with the process you go through!

OH MY GOD YOURE MY LIFE SAVIOUR!!! THANK YOU SO MUCH!!

Forgot to round the last one to 5.7x10^2 because there are only 2 SF in the ounce measurement. Maybe I am wrong but I see the oz and in measurements are not combined together so I treat them as separate problems in this case

Very simple to do , when you know the formula , and how to use the formula for a given problem. I love math - I get a high off it. By the way - good presentation Have. a nice day everybody!

Thanks!!

e seems to be wrong I believe. e) should be 2 decimal places, the lowest not sure why you took the biggest one in this case?

This is the opposite of what you said in the previous section regarding heat and temp, perhaps you flipped them

Wow, I did this accurately.

You could have done the initial equation, for example: Ca(C6H11NHSO3)2 (s) + 2HCl (aq) -> 2C6H11NHSO3H (aq) + CaCl2 (s). I'm not quite sure if it's part of the exercise.

Very helpful.

u sound like technoblade

wait for it to be decelerating doesn't that mean the car wheels must be slipping?

My dawg is OP

When finding time, why couldn't we have used t = d/v ? Thank you

Hi! I tried solving this another way but it didn't work.... How come I wouldn't be able to use the 25m and 40m information to get the angle, then use than angle in solving for x and y direction velocities? (I.e., drawing 2 triangles, one with distance and one with velocities). How come this doesn't work? I wouldn't think to use the time equation here, intuitively...

In both liquids and solids, the higher the temperature the more vigorously the particles jiggle about randomly.

So, FL is not the normal force on the leg?

Thank you ❤❤

I left the first equation as it is, multiplied the 2nd equation by 3 and multiplied the 3rd equation by 2. I added them side by side. I got the following equation. 4NH3+8O2---->4HNO3+4H2O I divided all the coefficients by 4 to get 1 mol HNO3. I found the enthalpy change 381.Can you Check?

Currently doing my precalculus homework…this helped me so much!!!

why can't I use the x =vt - 1/2at^2. I put that in the calculator but couldn't get the same result

Your videos helped me pass my Physics class this year! Thank you for all that you do! 😊

I will be taking organic chemistry and I would love it if you made I a sequence for it! You have helped me so much and made chemistry very understandable!

Bless ur heart thank you

thank you so much!!

I'm oxidized now!😄

Why is it not an acid-base reaction?

You have literally saved my life in chemistry. SNHU does not give any kind of video tutorials, your numbers are different but it is the same equation and I really don't believe that I could have learned chem at all without you!!!

Thank you. Great stuff. As an autodidactic learner, I sometimes find it harder than students in a class. But as soon as I hear your voices, I relax because I know that everything will be clearer afterwards.

I think you forgot to divide by 2 at 22:07 for the molar solubility since OH- has a coefficient of 2. This would reduce the amount of dissolved Mg2+ by half and slightly lower the answer to 3.99.

How come we don't account for the amount of A- base generated from the weak acid disassociating at 7:30?

Thank you for all you do! Your voice also sounds a little like Miranda's from Sex and the City.